Respuesta :

mreijepatmat
To get a triplet : 13C1 * 4C3

To get a pair : 12C1 * 4C2

Total possibility = 52C5

P(full) = [(13C1 * 4C3) * 12C1 * 4C2] / 52C5

If my calculation is right, the P(full) =0.144%

Stephaniereplogle

Answer:

24/2598960 or

0.000009234463 or

1/108290