Solution
For this case we have the following number given:
[tex]-3+\sqrt[]{3}i[/tex]We can see that x = -3 and y = - sqrt(3)
The angle is given by:
[tex]\arctan (\frac{-\sqrt[]{3}}{3})=-30=-\frac{\pi}{6}[/tex]The radius would be:
[tex]r=\sqrt[]{(3)^2+(-\sqrt[]{3})^2}=\sqrt[]{12}[/tex]And the polar form would be given by:
[tex]z=\sqrt[]{12}(\cos (-\frac{\pi}{6})+i\sin (-\frac{\pi}{6}))\text{ }[/tex]