Recall that the change of base formula for logarithms is:
[tex]\log_a(b)=\frac{\log_x(b)}{\log_x(a)}.[/tex]
Using the change of base formula for logarithms to the given logarithm we get:
[tex]\log_354=\frac{\log_8(54)}{\log_8(3)}.[/tex]
Therefore:
[tex]\log_3(54)=3.631.[/tex]
And:
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