Answer:
The answer is the option C
[tex]1+\frac{2}{5}x[/tex]
Step-by-step explanation:
we have
[tex]2+\frac{3}{5}x-1-\frac{1}{5}x[/tex]
Group terms
[tex]2+\frac{3}{5}x-1-\frac{1}{5}x=(\frac{3}{5}x-\frac{1}{5}x)+(2-1)[/tex]
[tex]=(\frac{2}{5}x)+(1)[/tex]
[tex]=1+\frac{2}{5}x[/tex]
