- First term=a=1
- Common difference=d=-3
Note down the Formula first
[tex]\boxed{\star\sf a_n=a+(n-1)d}[/tex]
[tex]\\ \sf\ast\Rrightarrow a_{12}=1+(12-1)(-3)[/tex]
[tex]\\ \sf\ast\Rrightarrow a_{12}=1+11(-3)[/tex]
[tex]\\ \sf\ast\Rrightarrow a_{12}=1-33[/tex]
[tex]\\ \sf\ast\Rrightarrow a_{12}=-32[/tex]
Option D is correct
