Given:
Consider the given equation is:
[tex](2\cdot 2^2)^x=64[/tex]
To find:
The value of x.
Solution:
We have,
[tex](2\cdot 2^2)^x=64[/tex]
It can be written as:
[tex](2\cdot 4)^x=8\times 8[/tex]
[tex]8^x=8^2[/tex]
On comparing the exponents of both sides, we get
[tex]x=2[/tex]
Therefore, the value of x is 2.
