Given:
In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.
To find:
The value of sine of ∠J.
Solution:
In a right angle triangle,
[tex]\sin\theta =\dfrac{Perpendicular}{Hypotenuse}[/tex]
In triangle JKL,
[tex]\sin J =\dfrac{LK}{KJ}[/tex]
[tex]\sin J =\dfrac{39}{89}[/tex]
[tex]\sin J =0.4382[/tex]
[tex]\sin J \approx 0.44[/tex]
Therefore, the value of sine of ∠J is about 0.44.
