Answer:
solution given:
product of (4a-5b) and (3a+4b-2c) is:
- (4a-5b)*(3a+4b-2c)
- 4a(3a+4b-2c)-5b(3a+4b-2c)
- 12a²+16ab-8ac -(15ab+20b²-10bc)
- 12a²+16ab-8ac-15ab-20b²+10bc
- 12a²+16ab-15ab+10bc-8ac-20b²
- 12a²+ab+10bc-8ac-20b²
the value of the product when A=2 b-3 and C= -2 :
(4a-5b)*(3a+4b-2c)
- (4*2-5*(-3))*(3*2+4*(-3)-2*(-2))
- (8+15)(6-12+4)
- 23*(-2)
- -46
