Answer:
its 0.547g
Explanation:
for normality; we have W=(NEV)/1000
similarly for molarity; we have W= (MMwV)/1000
here the molarity is given... molecular weight of NaOH is 40 and the volume to be prepared is 88.25 ML so by formula, we have W=(0.155×40×88.25)/1000 which is equal to 0.547g. Hence, W=0.547g
