Answer:
[tex]2\sqrt{3}[/tex]
Step-by-step explanation:
I'm assuming the angles are in degrees.
[tex]2x \tan(60\º)=10+\csc(30\º)[/tex]
[tex]$2x\cdot \sqrt{3}=10+\frac{1}{\sin(30\º)} $[/tex]
[tex]$2x\cdot \sqrt{3}=10+\frac{1}{\frac{1}{2} } $[/tex]
[tex]$2x\cdot \sqrt{3}=10+2} $[/tex]
[tex]$x=\frac{12}{2\sqrt{3}} $[/tex]
[tex]$x=\frac{6}{\sqrt{3}} =\frac{6\sqrt{3}} {3} }=2\sqrt{3} $[/tex]
