Answer:
R = 73.25 m
Explanation:
We have,
Initial speed of the ball is 27 m/s
It is projected at an angle of 40 degrees
The maximum range of the ball is given by :
[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]
Plugging all the values we get :
[tex]R=\dfrac{(27)^2\sin2(40)}{9.8}\\R=73.25\ m[/tex]
So, the maximum range of the ball is 73.25 m
