HotaroKim
HotaroKim HotaroKim
  • 02-03-2020
  • Physics
contestada

A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh

Respuesta :

MathPhys
MathPhys MathPhys
  • 02-03-2020

Explanation:

30 minutes is 1800 seconds.

Power = energy / time

P = 1100 J / 1800 s

P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

To find resistance, you need to be given either the voltage or the current.

Answer Link

Otras preguntas

Reduce the ratio to its lowest form 45:20
PLEASE HELP What is he biggest county in Washington in terms of population?
I am having trouble with this equation 3 ( x-5 ) =9can anyone help pls
To help black southerners adjust to freedom, Congress created a. the Thirteenth Amendment. b. the Captured and Abandoned Property Act. c. the Ten Percent Plan.
why isn't the United States one of the top 10 cacao producing countries
Shawn and Ellie are construction workers. Shawn can complete a concrete job in 5 hours, while Ellie can complete it in 7 hours. The foreman says that it will ta
What do you think will be the biggest problem/issue for the Criminal Justice system ten years from now?
whats 4x+-1x equal ?
Together, Katya and Mimi have 480 pennies in their piggy banks. After Katya lost ½ of her pennies and Mimi lost 2/3 of her pennies, they both had an equal num
Is the word rash an adjective noun and verb?