Answer:
θ = 36°
Explanation:
given,
F₁ = 22.8 N
F₂ = 16.6 N
magnitude of force = ?
direction of force = ?
[tex]F = \sqrt{F_1^2 + F_2^2}[/tex]
[tex]F = \sqrt{22.8^2 + 16.6^2}[/tex]
[tex]F = \sqrt{795.4}[/tex]
F = 28.20 N
direction
[tex]\theta = tan^{-1}(\dfrac{F_2}{F_1})[/tex]
[tex]\theta = tan^{-1}(\dfrac{16.6}{22.8})[/tex]
[tex]\theta = tan^{-1}(0.728)[/tex]
θ = 36°
