corinam9851 corinam9851
  • 02-04-2019
  • Chemistry
contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

jamuuj jamuuj
  • 11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05  

m2=0.015 and

v2=25.00mL  

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

    = 7.50 mL

Answer Link

Otras preguntas

what are the similarities between insects and humans
To calculate the area of the front surface of a box,you (a) add the length to the height (b) add twice the length to twice the height ( c) multiply the length b
What unions were open to African Americans in the 1920s?
How do we solve that problem 1/4(x-3)=3x-11/4x-3
does 20 hundredths equal 2 thousandths
How do round, spiral, and rod-shaped bacteria look like?
select difference of (8x2-3x3) - (2x2-5x3)
The sum of two numbers is 104 and one exceed the other by 10. What are the numbers?
Log4(6x-8)=3 Help please
A cable is lifting a construction worker and a crate. The weights of the worker and crate are 965 N and 1510 N, respectively. The acceleration of the cable is