melindamackay83 melindamackay83
  • 04-01-2019
  • Mathematics
contestada

At the pet fair Darlene’s dog weighed five times as much as leaders dog. Together the dogs weighed 84 pounds how much did each dog weigh?

Respuesta :

musiclover10045
musiclover10045 musiclover10045
  • 04-01-2019

Answer:

Let the weight of the leader dog = X

Then Darlene's dog weighs = 5X ( fives times as much)

Now add both together to equal 84 pounds:

5X + X = 84


Simplify:

6x = 84

Divide both sides by 6:

x = 84 / 6

x = 14


The leader dog weighs 14 pounds.

Darlene's dog weighs 70 pounds.


Answer Link

Otras preguntas

What is the prefix of active
what act did the united states government pass in order to be able to move Native American of their lands into the Indian's Territory? A) Native American Act B)
Brody added a fraction to 5/6 to get 31/30. Use the equation a/b + c/d = (ad +bc)/ bd to find the fraction he added
what does a 220 degree angle look like?
4/3v^2x -5/6vx^3 what is this answer for algebra
which of the following did not trigger Haiti's fight for independence
1.How would you describe a person that wants to help his family ? 2. How would you describe a person that is hopeful?
PLEASE CHECK MY ANSWERS (PART 2)
if hares with long legs run faster than hares with short legs, which hares do you expect would be most likely to survive and reproduce
Which describes the significance of Athens's victory in the Persian Wars? A. Athenians gained new confidence in their own abilities, which led to a golden